4^{x+1}=5^x

Lösung

4^{x + 1} = 5^{x}

x = \frac{2 ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

Dezimale

x = 6.21256 \dots

Schritte zur Lösung

4^{x + 1} = 5^{x}

Wende Exponentenregel an

(x + 1) ln (4) = x ln (5)

Löse

(x + 1) ln (4) = x ln (5) : x = \frac{2 ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

x = \frac{2 ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

5^{2 x} = 3^{3 x + 1}

2^{x + 2} - 2^{x + 5} + 7 = 0

95 = 2 7^{x}

2^{2 x - 5} = 16

2 (\frac{1}{8})^{1 - 2 x} = 1 6^{x + 6}