9^{x-2}=8

Lösung

9^{x - 2} = 8

x = \frac{3 ln ( 2 )}{2 ln ( 3 )} + 2

Dezimale

x = 2.94639 \dots

Schritte zur Lösung

9^{x - 2} = 8

Wende Exponentenregel an

(x - 2) ln (9) = ln (8)

Löse

(x - 2) ln (9) = ln (8) : x = \frac{3 ln ( 2 )}{2 ln ( 3 )} + 2

x = \frac{3 ln ( 2 )}{2 ln ( 3 )} + 2

\frac{27}{3 ^{1 - 3 x}} = 9

\frac{4 ^{x - 1}}{2 ^{x}} = 6

so l v e f or x, f = a^{x} + q

0.8 = 0. 9^{x}

2^{11 - x} = 2^{x + 1}