4^{x-1}=5^{x+1}

Lösung

4^{x - 1} = 5^{x + 1}

x = \frac{ln ( 20 )}{2 ln ( 2 ) - ln ( 5 )}

Dezimale

x = - 13.42513 \dots

Schritte zur Lösung

4^{x - 1} = 5^{x + 1}

Wende Exponentenregel an

(x - 1) ln (4) = (x + 1) ln (5)

Löse

(x - 1) ln (4) = (x + 1) ln (5) : x = \frac{ln ( 20 )}{2 ln ( 2 ) - ln ( 5 )}

x = \frac{ln ( 20 )}{2 ln ( 2 ) - ln ( 5 )}

9^{8 x - 4} = \frac{1}{( 81 ) ^{2 x - 5}}

\frac{1}{4 ^{x - 2}} = 64

5^{a} = 1

0 = \frac{- 28}{2 ^{5 x + 5}} + 7

8 e^{x} - 5 = 0