5^x=e^{x-1}

Lösung

5^{x} = e^{x - 1}

x = - \frac{1}{ln ( 5 ) - 1}

Dezimale

x = - 1.64085 \dots

Schritte zur Lösung

5^{x} = e^{x - 1}

Wende Exponentenregel an

x ln (5) = x - 1

Löse

x ln (5) = x - 1 : x = - \frac{1}{ln ( 5 ) - 1}

x = - \frac{1}{ln ( 5 ) - 1}

x^{l o g_{5} (x) - 2} = 125

5^{4 X + 20} = 5^{12 X + 20}

(1.09)^{t} = 4

2 e^{2 x} = e^{- x}

e^{x - 5} = 15