(x+1)^{x^2-4}=(x+1)^{2-x}

解答

(x + 1)^{x^{2} - 4} = (x + 1)^{2 - x}

x = 0, x = 2

求解步骤

(x + 1)^{x^{2} - 4} = (x + 1)^{2 - x}

使用指数运算法则

(x^{2} - 4) ln (x + 1) = (2 - x) ln (x + 1)

解

(x^{2} - 4) ln (x + 1) = (2 - x) ln (x + 1) : x = 0, x = 2

x = 0, x = 2

(\frac{1000000}{2 ^{d}}) = 1950

2^{6 x + 12} = 3 2^{2 x + 4}

40 = 2^{x}

1^{x} = 1.2

e^{a^{5}} = 2.4