|y+3|=1

Lösung

∣ y + 3 ∣ = 1

y = - 4 or y = - 2

Schritte zur Lösung

∣ y + 3 ∣ = 1

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

y + 3 = - 1 or y + 3 = 1

y + 3 = - 1 or y + 3 = 1

y = - 4 or y = - 2

3.5 ∣ 6 x - 2 ∣ = 3.5

∣ 3 t - 2 ∣ + 6 = 2

∣ 3 x + 4 ∣ + 8 = x

\frac{5}{x} - 2 = 1

x^{2} - 4 x + 5 = 2