2=log_{3}(x+7)

Lösung

2 = lo g_{3} (x + 7)

x = 2

Schritte zur Lösung

2 = lo g_{3} (x + 7)

Wende die log Regel an

9 = x + 7

Löse

9 = x + 7 : x = 2

x = 2

e^{3} = ln (x)

1 0^{5} = lo g_{10} (x)

lo g_{b} (x + 2) = lo g_{b} (x) + 2

ln (5 x + 4) = 7.9

lo g_{6} (2 x - 7) = 4