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受欢迎的代数 >

solvefor x,x^2-y^2ifx=-3

解答

求解

x, x^{2} - y^{2} i f x = - 3

解答

x = - \frac{- y ^{2} f + y ^{4} f ^{2} + 12}{2} i, x = - \frac{- y ^{2} f - y ^{4} f ^{2} + 12}{2} i, x = \frac{- 12 - y ^{4} f ^{2}}{2} + \frac{y ^{2} f}{2} i, x = - \frac{- 12 - y ^{4} f ^{2}}{2} + \frac{y ^{2} f}{2} i

求解步骤

x^{2} - y^{2} i f x = - 3

替代

x = a + bi

(a + bi)^{2} - y^{2} i f (a + bi) = - 3

展开

(a + bi)^{2} - y^{2} i f (a + bi) : (a^{2} - b^{2} + y^{2} f b) + i (2 ab - y^{2} f a)

a^{2} - b^{2} + y^{2} f b + i (2 ab - y^{2} f a) = - 3

将

- 3

改写成标准复数形式:

- 3 + 0 i

a^{2} - b^{2} + y^{2} f b + i (2 ab - y^{2} f a) = - 3 + 0 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[a^{2} - b^{2} + y^{2} f b = - 3 2 ab - y^{2} f a = 0]

[a^{2} - b^{2} + y^{2} f b = - 3 2 ab - y^{2} f a = 0] : a = 0, a = 0, a = \frac{- 12 - y ^{4} f ^{2}}{2}, a = - \frac{- 12 - y ^{4} f ^{2}}{2}, b = - \frac{- y ^{2} f + y ^{4} f ^{2} + 12}{2} b = - \frac{- y ^{2} f - y ^{4} f ^{2} + 12}{2} b = \frac{y ^{2} f}{2} b = \frac{y ^{2} f}{2}

x = a + bi

代回

x = - \frac{- y ^{2} f + y ^{4} f ^{2} + 12}{2} i, x = - \frac{- y ^{2} f - y ^{4} f ^{2} + 12}{2} i, x = \frac{- 12 - y ^{4} f ^{2}}{2} + \frac{y ^{2} f}{2} i, x = - \frac{- 12 - y ^{4} f ^{2}}{2} + \frac{y ^{2} f}{2} i

流行的例子

(m-1/2)(m-3-i)=0

(m - \frac{1}{2}) (m - 3 - i) = 0

solvefor x,y=-x^2+1graficar

so l v e f or x, y = - x^{2} + 1 g r a f i c a r

z^{2} + 4 i = 0

(1-2i)/z =(1+i)^2

\frac{1 - 2 i}{z} = (1 + i)^{2}

(a+2i)/(3+bi)=3

\frac{a + 2 i}{3 + bi} = 3