solvefor y,e^{sqrt(y)}=x^2

Lösung

löse nach

y, e^{y} = x^{2}

y = 4 ln^{2} (x) {x \geq 1}

Schritte zur Lösung

e^{y} = x^{2}

Wende Exponentenregel an

y = 2 ln (x)

Löse

y = 2 ln (x) : y = 4 ln^{2} (x) {x \geq 1}

y = 4 ln^{2} (x) {x \geq 1}

(x) (x) = 2 x

9 x^{2} - 2 x - 3 = 0

co m pl e t es q u a re x^{2} - 4 x - 2 = 0

- 3 x^{2} + 12 x + 4 = 0

2 x^{2} + 12 x = 4