4x^2=(3x)/(3x+1)+1/(3x+1)

解

4 x^{2} = \frac{3 x}{3 x + 1} + \frac{1}{3 x + 1}

x = - \frac{1}{2}, x = \frac{1}{2}

十進法表記

x = - 0.5, x = 0.5

解答ステップ

4 x^{2} = \frac{3 x}{3 x + 1} + \frac{1}{3 x + 1}

以下で両辺を乗じる:

3 x + 1

4 x^{2} (3 x + 1) = 3 x + 1

解く

4 x^{2} (3 x + 1) = 3 x + 1 : x = - \frac{1}{3}, x = - \frac{1}{2}, x = \frac{1}{2}

x = - \frac{1}{3}, x = - \frac{1}{2}, x = \frac{1}{2}

解を検算する

未定義の (特異) 点を求める:

x = - \frac{1}{3}

equationは以下で未定義のため:

- \frac{1}{3}

x = - \frac{1}{2}, x = \frac{1}{2}