1/(x-2)+3/(x+3)=6

解

\frac{1}{x - 2} + \frac{3}{x + 3} = 6

x = \frac{- 1 + 199}{6}, x = - \frac{1 + 199}{6}

十進法表記

x = 2.18445 \dots, x = - 2.51778 \dots

解答ステップ

\frac{1}{x - 2} + \frac{3}{x + 3} = 6

LCMで乗じる

x + 3 + 3 (x - 2) = 6 (x - 2) (x + 3)

解く

x + 3 + 3 (x - 2) = 6 (x - 2) (x + 3) : x = \frac{- 1 + 199}{6}, x = - \frac{1 + 199}{6}

x = \frac{- 1 + 199}{6}, x = - \frac{1 + 199}{6}

解を検算する

未定義の (特異) 点を求める:

x = 2, x = - 3

未定義のポイントを解に組み合わせる:

x = \frac{- 1 + 199}{6}, x = - \frac{1 + 199}{6}