10^{4x}=72

Lösung

1 0^{4 x} = 72

x = \frac{ln ( 72 )}{4 ln ( 10 )}

Dezimale

x = 0.46433 \dots

Schritte zur Lösung

1 0^{4 x} = 72

Wende Exponentenregel an

4 x ln (10) = ln (72)

Löse

4 x ln (10) = ln (72) : x = \frac{ln ( 72 )}{4 ln ( 10 )}

x = \frac{ln ( 72 )}{4 ln ( 10 )}

6^{- 2 x} \cdot 6^{- x} = \frac{1}{216}

3^{2} 9^{2} = 3^{x}

(25)^{2 x - 1} = 5^{x + 4}

3^{x} - 3^{x + 3} = - 78

0.4 = (\frac{1}{1.06})^{n}