3^{1-2x}=4^{2x+5}

Lösung

3^{1 - 2 x} = 4^{2 x + 5}

x = - \frac{10 ln ( 2 ) - ln ( 3 )}{2 ln ( 12 )}

Dezimale

x = - 1.17365 \dots

Schritte zur Lösung

3^{1 - 2 x} = 4^{2 x + 5}

Wende Exponentenregel an

(1 - 2 x) ln (3) = (2 x + 5) ln (4)

Löse

(1 - 2 x) ln (3) = (2 x + 5) ln (4) : x = - \frac{10 ln ( 2 ) - ln ( 3 )}{2 ln ( 12 )}

x = - \frac{10 ln ( 2 ) - ln ( 3 )}{2 ln ( 12 )}

3^{4 x} - 3^{2 x} - 6 = 0

(- 3)^{x} = (- 3)^{13}

3^{\frac{x}{4}} = 2

3^{x} = 7^{x}

so l v e f or y, \frac{1}{3 ^{- 4}} = x^{y}