1/125 =25^{x+5}

Lösung

\frac{1}{125} = 2 5^{x + 5}

x = - \frac{13}{2}

Dezimale

x = - 6.5

Schritte zur Lösung

\frac{1}{125} = 2 5^{x + 5}

Wende Exponentenregel an

- 3 = 2 (x + 5)

Löse

- 3 = 2 (x + 5) : x = - \frac{13}{2}

x = - \frac{13}{2}

5^{x - 3} = 25

3^{x^{2} - 4 x} = 4^{x^{2} - 4 x}

3^{5 x} = 34

2 e^{x} (x - 1) + 1 = 0

5^{5} = 312 5^{3 x + 1}