2^{-3n}*1/4 =2^{n+2}

Lösung

2^{- 3 n} \cdot \frac{1}{4} = 2^{n + 2}

n = - 1

Schritte zur Lösung

2^{- 3 n} \cdot \frac{1}{4} = 2^{n + 2}

Wende Exponentenregel an

- 3 n - 2 = n + 2

Löse

- 3 n - 2 = n + 2 : n = - 1

n = - 1

(1.01 2^{t - 1998}) = 1.1707

2^{4 x - 2} = 4^{x + 2}

5^{3 x + 8} = 2 5^{2 x}

0.0 1^{x} = 100

\frac{1}{3} e^{3 t} = \frac{1}{2}