3(2^x)=4^{x+1}

Lösung

3 (2^{x}) = 4^{x + 1}

x = - \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 2 )}

Dezimale

x = - 0.41503 \dots

Schritte zur Lösung

3 (2^{x}) = 4^{x + 1}

Wende Exponentenregel an

ln (3) + x ln (2) = 2 (x + 1) ln (2)

Löse

ln (3) + x ln (2) = 2 (x + 1) ln (2) : x = - \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 2 )}

x = - \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 2 )}