5^{3x}=5^{7x-2}

Lösung

5^{3 x} = 5^{7 x - 2}

x = \frac{1}{2}

Dezimale

x = 0.5

Schritte zur Lösung

5^{3 x} = 5^{7 x - 2}

Wende Exponentenregel an

3 x = 7 x - 2

Löse

3 x = 7 x - 2 : x = \frac{1}{2}

x = \frac{1}{2}

2 7^{x - 3} = 8 1^{2 x - 4}

2 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2}) = 0

2^{3 - x} = 4^{x}

e^{2 x} + 2 e^{x} - 3 = 0

e^{- x} (1 - x) = 0