49^{x+1}=(1/7)^x

Lösung

4 9^{x + 1} = (\frac{1}{7})^{x}

x = - \frac{2}{3}

Dezimale

x = - 0.66666 \dots

Schritte zur Lösung

4 9^{x + 1} = (\frac{1}{7})^{x}

Wende Exponentenregel an

2 (x + 1) = - x

Löse

2 (x + 1) = - x : x = - \frac{2}{3}

x = - \frac{2}{3}

e^{x + 1} - 2^{3 - x} = 0

91500 = 100000 - 272000 (\frac{1}{2})^{x}

3^{x} + x = 11

3^{2 - x} = 3^{x^{2}}

9^{2 x} - 3 \cdot 9^{x} + 2 = 0