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受欢迎的代数 >

solvefor x,x^2+(y-cbrt(x^2))^2=25

解答

求解

x, x^{2} + (y - c b r t (x^{2}))^{2} = 25

解答

x = \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}, x = - \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}, x = \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}, x = - \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}

求解步骤

x^{2} + (y - c b r t (x^{2}))^{2} = 25

展开

x^{2} + (y - c b r t (x^{2}))^{2} : x^{2} + y^{2} - 2 c b x^{2} yr t + c^{2} b^{2} x^{4} r^{2} t^{2}

x^{2} + y^{2} - 2 c b x^{2} yr t + c^{2} b^{2} x^{4} r^{2} t^{2} = 25

将

25

para o lado esquerdo

x^{2} + y^{2} - 2 c b x^{2} yr t + c^{2} b^{2} x^{4} r^{2} t^{2} - 25 = 0

改写成标准形式

a_{n} x^{n} + \dots + b x + c = 0

c^{2} b^{2} r^{2} t^{2} x^{4} + (1 - 2 c b yr t) x^{2} + y^{2} - 25 = 0

用

u = x^{2}

和

u^{2} = x^{4}

改写方程式

c^{2} b^{2} r^{2} t^{2} u^{2} + (1 - 2 c b yr t) u + y^{2} - 25 = 0

解

c^{2} b^{2} r^{2} t^{2} u^{2} + (1 - 2 c b yr t) u + y^{2} - 25 = 0 : u = \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c ^{2} b ^{2} r ^{2} t ^{2}}, u = \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c ^{2} b ^{2} r ^{2} t ^{2}}; c^{2} b^{2} r^{2} t^{2} \neq = 0

u = \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c ^{2} b ^{2} r ^{2} t ^{2}}, u = \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c ^{2} b ^{2} r ^{2} t ^{2}}; c^{2} b^{2} r^{2} t^{2} \neq = 0

代回

u = x^{2}

，求解

x

解

x^{2} = \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c ^{2} b ^{2} r ^{2} t ^{2}} : x = \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}, x = - \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}

解

x^{2} = \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c ^{2} b ^{2} r ^{2} t ^{2}} : x = \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}, x = - \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}

解为

x = \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}, x = - \frac{- 1 + 2 c b yr t + 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}, x = \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}, x = - \frac{- 1 + 2 c b yr t - 1 - 4 c b yr t + 100 c ^{2} b ^{2} r ^{2} t ^{2}}{2 c b r t}

作图

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