5x^2-20x=0

解

5 x^{2} - 20 x = 0

x = 4, x = 0

解答ステップ

5 x^{2} - 20 x = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 0 = 20

x_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 5}

解を分離する

x_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 5}, x_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 5}

x = \frac{- ( - 20 ) + 20}{2 \cdot 5} : 4

x = \frac{- ( - 20 ) - 20}{2 \cdot 5} : 0

二次equationの解:

x = 4, x = 0