ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

solvefor x,fx= 1/(sqrt(x^2-y^2))

解

解く

x, f x = \frac{1}{x ^{2} - y ^{2}}

解

x = \frac{y ^{2} f + y ^{4} f ^{2} + 4}{2 f}, x = - \frac{y ^{2} f + y ^{4} f ^{2} + 4}{2 f}, x = \frac{y ^{2} f - y ^{4} f ^{2} + 4}{2 f}, x = - \frac{y ^{2} f - y ^{4} f ^{2} + 4}{2 f}

解答ステップ

f x = \frac{1}{x ^{2} - y ^{2}}

以下で両辺を乗じる:

x^{2} - y^{2}

f x x^{2} - y^{2} = \frac{1}{x ^{2} - y ^{2}} x^{2} - y^{2}

簡素化

f x x^{2} - y^{2} = 1

両辺を2乗する:

x^{4} f^{2} - x^{2} y^{2} f^{2} = 1

x^{4} f^{2} - x^{2} y^{2} f^{2} = 1

解く

x^{4} f^{2} - x^{2} y^{2} f^{2} = 1 : x = \frac{y ^{2} f + y ^{4} f ^{2} + 4}{2 f}, x = - \frac{y ^{2} f + y ^{4} f ^{2} + 4}{2 f}, x = \frac{y ^{2} f - y ^{4} f ^{2} + 4}{2 f}, x = - \frac{y ^{2} f - y ^{4} f ^{2} + 4}{2 f}

x = \frac{y ^{2} f + y ^{4} f ^{2} + 4}{2 f}, x = - \frac{y ^{2} f + y ^{4} f ^{2} + 4}{2 f}, x = \frac{y ^{2} f - y ^{4} f ^{2} + 4}{2 f}, x = - \frac{y ^{2} f - y ^{4} f ^{2} + 4}{2 f}

グラフ

人気の例

3x^{1/3}+2x^{2/3}=5

3 x^{\frac{1}{3}} + 2 x^{\frac{2}{3}} = 5

sqrt(5x+5)=sqrt(4x)+1

5 x + 5 = 4 x + 1

20.5sqrt(x+4)-41=0.02x^3+10.4

20.5 x + 4 - 41 = 0.02 x^{3} + 10.4

-4=-8+sqrt(32-2n)

- 4 = - 8 + 32 - 2 n

6 x = x