faktorisieren (x+4)^2-(8x+7)^2

Lösung

faktorisieren

(x + 4)^{2} - (8 x + 7)^{2}

- (9 x + 11) (7 x + 3)

Schritte zur Lösung

(x + 4)^{2} - (8 x + 7)^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(x + 4)^{2} - (8 x + 7)^{2} = ((x + 4) + (8 x + 7)) ((x + 4) - (8 x + 7))

= ((x + 4) + (8 x + 7)) ((x + 4) - (8 x + 7))

Vereinfache

((x + 4) + (8 x + 7)) ((x + 4) - (8 x + 7)) : (9 x + 11) (- 7 x - 3)

= (9 x + 11) (- 7 x - 3)

Faktorisiere

- 7 x - 3 : - (7 x + 3)

= (9 x + 11) (- (7 x + 3))

Apply rule:

a (- b) = - ab

(9 x + 11) (- (7 x + 3)) = - (9 x + 11) (7 x + 3)

= - (9 x + 11) (7 x + 3)

s im pl i f y (81 x^{12})^{1.25}

f a c t or x - y - x y + x^{2}

f a c t or 4 - 2 x - 30 y + 15 x y

- 4 x < - 8

3 x^{2} + 9 x + 2 = 0