|4x-5|>= 6

Lösung

∣ 4 x - 5 ∣ \geq 6

x \leq - \frac{1}{4} or x \geq \frac{11}{4}

Intervall-Notation

(- \infty, - \frac{1}{4}] \cup [\frac{11}{4}, \infty)

Dezimale

x \leq - 0.25 or x \geq 2.75

Schritte zur Lösung

∣ 4 x - 5 ∣ \geq 6

Wende Absoluteregel an: Wenn

∣ u ∣ \geq a, a > 0

dann

u \leq - a

u \geq a

4 x - 5 \leq - 6 or 4 x - 5 \geq 6

4 x - 5 \leq - 6 or 4 x - 5 \geq 6

x \leq - \frac{1}{4} or x \geq \frac{11}{4}

2 x + 6 > 12

x + 11 < 21

\frac{1}{x ^{\frac{3}{2}}}

8 + 3 x \geq 20

f a c t or 42 m^{5} n + 28 m^{4}