因式分解 4m^2-4mn+n^2

解答

因式分解

4 m^{2} - 4 mn + n^{2}

(2 m - n)^{2}

求解步骤

4 m^{2} - 4 mn + n^{2}

改写为形式

a^{2} + 2 ab + b^{2} :

4 m^{2} = (2 m)^{2}

- 4 mn = - 2 \cdot 2 mn

= (2 m)^{2} - 2 \cdot 2 mn + n^{2}

使用完全平方公式:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 m)^{2} - 2 \cdot 2 mn + n^{2} = (2 m - n)^{2}

= (2 m - n)^{2}

f a c t or - x^{2} - 6 x + 16

s im pl i f y \frac{180}{3}

(x - 3)^{2} \leq 5 - x

x^{2} - 13 x + 42 = 0

x - 5 \leq 4 x + 7