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受欢迎的代数 >

20s^2+20s+10=0

解答

20 s^{2} + 20 s + 10 = 0

解答

s = - \frac{1}{2} + i \frac{1}{2}, s = - \frac{1}{2} - i \frac{1}{2}

求解步骤

20 s^{2} + 20 s + 10 = 0

使用求根公式求解

s_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 20 \cdot 10}{2 \cdot 20}

化简

2 0^{2} - 4 \cdot 20 \cdot 10 : 20 i

s_{1, 2} = \frac{- 20 \pm 20 i}{2 \cdot 20}

将解分隔开

s_{1} = \frac{- 20 + 20 i}{2 \cdot 20}, s_{2} = \frac{- 20 - 20 i}{2 \cdot 20}

s = \frac{- 20 + 20 i}{2 \cdot 20} : - \frac{1}{2} + i \frac{1}{2}

s = \frac{- 20 - 20 i}{2 \cdot 20} : - \frac{1}{2} - i \frac{1}{2}

二次方程组的解是:

s = - \frac{1}{2} + i \frac{1}{2}, s = - \frac{1}{2} - i \frac{1}{2}

作图

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