s^2+4s+3=0

解

s^{2} + 4 s + 3 = 0

s = - 1, s = - 3

解答ステップ

s^{2} + 4 s + 3 = 0

解くとthe二次式

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

s_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

解を分離する

s_{1} = \frac{- 4 + 2}{2 \cdot 1}, s_{2} = \frac{- 4 - 2}{2 \cdot 1}

s = \frac{- 4 + 2}{2 \cdot 1} : - 1

s = \frac{- 4 - 2}{2 \cdot 1} : - 3

二次equationの解:

s = - 1, s = - 3