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Beliebt Algebra >

faktorisieren 2x^4+15x^3+17x^2+3x-1

Lösung

faktorisieren

2 x^{4} + 15 x^{3} + 17 x^{2} + 3 x - 1

Lösung

(x + 1) (2 x + 1) (x^{2} + 6 x - 1)

Schritte zur Lösung

2 x^{4} + 15 x^{3} + 17 x^{2} + 3 x - 1

Wende den rationalen Nullstellentest an

= (x + 1) \frac{2 x ^{4} + 15 x ^{3} + 17 x ^{2} + 3 x - 1}{x + 1}

\frac{2 x ^{4} + 15 x ^{3} + 17 x ^{2} + 3 x - 1}{x + 1} = 2 x^{3} + 13 x^{2} + 4 x - 1

= (x + 1) (2 x^{3} + 13 x^{2} + 4 x - 1)

Faktorisiere

2 x^{3} + 13 x^{2} + 4 x - 1 : (2 x + 1) (x^{2} + 6 x - 1)

= (x + 1) (2 x + 1) (x^{2} + 6 x - 1)

Beliebte Beispiele

faktorisieren 3x^2+6xy+3y^2

f a c t or 3 x^{2} + 6 x y + 3 y^{2}

5 x - 6 = 3 x

(5x-3)/4-(x-2)/6 =(5-2x)/2

\frac{5 x - 3}{4} - \frac{x - 2}{6} = \frac{5 - 2 x}{2}

faktorisieren 8x^2+16x-64

f a c t or 8 x^{2} + 16 x - 64

faktorisieren 6x^2-17x+12

f a c t or 6 x^{2} - 17 x + 12