What is the derivative of f(x)=4x^{-3}+x^2+14 ?

The derivative of f(x)=4x^{-3}+x^2+14 is 2x-(12)/(x^4)

What is the first derivative of f(x)=4x^{-3}+x^2+14 ?

The first derivative of f(x)=4x^{-3}+x^2+14 is 2x-(12)/(x^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

f (x) = 4 x^{- 3} + x^{2} + 14

2 x - \frac{12}{x ^{4}}

Solution steps

\frac{d}{d x} (4 x^{- 3} + x^{2} + 14)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{- 3}) + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (14)

\frac{d}{d x} (4 x^{- 3}) = - \frac{12}{x ^{4}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (14) = 0

= - \frac{12}{x ^{4}} + 2 x + 0

Simplify

= 2 x - \frac{12}{x ^{4}}

What is the derivative of f(x)=4x^{-3}+x^2+14 ?
The derivative of f(x)=4x^{-3}+x^2+14 is 2x-(12)/(x^4)
What is the first derivative of f(x)=4x^{-3}+x^2+14 ?
The first derivative of f(x)=4x^{-3}+x^2+14 is 2x-(12)/(x^4)