What is laplacetransform 1/2 sin(4t) ?

The answer to laplacetransform 1/2 sin(4t) is 2/(s^2+16)

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laplacetransform 1/2 sin(4t)

laplace transform

\frac{1}{2} sin (4 t)

\frac{2}{s ^{2} + 16}

Solution steps

L {\frac{1}{2} sin (4 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= \frac{1}{2} L {sin (4 t)}

L {sin (4 t)} : \frac{4}{s ^{2} + 16}

= \frac{1}{2} \cdot \frac{4}{s ^{2} + 16}

Refine

\frac{1}{2} \frac{4}{s ^{2} + 16} : \frac{2}{s ^{2} + 16}

= \frac{2}{s ^{2} + 16}

What is laplacetransform 1/2 sin(4t) ?
The answer to laplacetransform 1/2 sin(4t) is 2/(s^2+16)