What is the solution for f^'(x)=((5x^2-9x+8))/(7x+6) ?

The solution for f^'(x)=((5x^2-9x+8))/(7x+6) is f(x)=(5x^2)/(14)-93/49 x+950/343 ln(7x+6)+c_{1}

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f^'(x)=((5x^2-9x+8))/(7x+6)

f^{^{'}} (x) = \frac{( 5 x ^{2} - 9 x + 8 )}{7 x + 6}

f (x) = \frac{5 x ^{2}}{14} - \frac{93}{49} x + \frac{950}{343} ln (7 x + 6) + c_{1}

Solution steps

f^{'} (x) = \frac{( 5 x ^{2} - 9 x + 8 )}{7 x + 6}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{5 x ^{2} - 9 x + 8}{7 x + 6} d x

\int \frac{5 x ^{2} - 9 x + 8}{7 x + 6} d x = \frac{5 x ^{2}}{14} - \frac{93}{49} x + \frac{950}{343} ln (7 x + 6) + c_{1}

f (x) = \frac{5 x ^{2}}{14} - \frac{93}{49} x + \frac{950}{343} ln (7 x + 6) + c_{1}

What is the solution for f^'(x)=((5x^2-9x+8))/(7x+6) ?
The solution for f^'(x)=((5x^2-9x+8))/(7x+6) is f(x)=(5x^2)/(14)-93/49 x+950/343 ln(7x+6)+c_{1}