What is the integral of (x+5)(x^2+5x-10) ?

The integral of (x+5)(x^2+5x-10) is (x^4)/4+(10x^3)/3+(15x^2)/2-50x+C

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integral of (x+5)(x^2+5x-10)

\int (x + 5) (x^{2} + 5 x - 10) d x

\frac{x ^{4}}{4} + \frac{10 x ^{3}}{3} + \frac{15 x ^{2}}{2} - 50 x + C

Solution steps

\int (x + 5) (x^{2} + 5 x - 10) d x

Expand

(x + 5) (x^{2} + 5 x - 10) : x^{3} + 10 x^{2} + 15 x - 50

= \int x^{3} + 10 x^{2} + 15 x - 50 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x + \int 10 x^{2} d x + \int 15 x d x - \int 50 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 10 x^{2} d x = \frac{10 x ^{3}}{3}

\int 15 x d x = \frac{15 x ^{2}}{2}

\int 50 d x = 50 x

= \frac{x ^{4}}{4} + \frac{10 x ^{3}}{3} + \frac{15 x ^{2}}{2} - 50 x

Add a constant to the solution

= \frac{x ^{4}}{4} + \frac{10 x ^{3}}{3} + \frac{15 x ^{2}}{2} - 50 x + C

What is the integral of (x+5)(x^2+5x-10) ?
The integral of (x+5)(x^2+5x-10) is (x^4)/4+(10x^3)/3+(15x^2)/2-50x+C