What is the integral of (3sec(x)tan(x)+4sec^2(x)) ?

The integral of (3sec(x)tan(x)+4sec^2(x)) is 3sec(x)+4tan(x)+C

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integral of (3sec(x)tan(x)+4sec^2(x))

\int (3 sec (x) tan (x) + 4 sec^{2} (x)) d x

3 sec (x) + 4 tan (x) + C

Solution steps

\int 3 sec (x) tan (x) + 4 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 sec (x) tan (x) d x + \int 4 sec^{2} (x) d x

\int 3 sec (x) tan (x) d x = 3 sec (x)

\int 4 sec^{2} (x) d x = 4 tan (x)

= 3 sec (x) + 4 tan (x)

Add a constant to the solution

= 3 sec (x) + 4 tan (x) + C

What is the integral of (3sec(x)tan(x)+4sec^2(x)) ?
The integral of (3sec(x)tan(x)+4sec^2(x)) is 3sec(x)+4tan(x)+C