What is the derivative of x^4-3x^3+2x^2 ?

The derivative of x^4-3x^3+2x^2 is 4x^3-9x^2+4x

What is the first derivative of x^4-3x^3+2x^2 ?

The first derivative of x^4-3x^3+2x^2 is 4x^3-9x^2+4x

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\frac{d}{d x} (x^{4} - 3 x^{3} + 2 x^{2})

4 x^{3} - 9 x^{2} + 4 x

Solution steps

\frac{d}{d x} (x^{4} - 3 x^{3} + 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (3 x^{3}) + \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

= 4 x^{3} - 9 x^{2} + 4 x

What is the derivative of x^4-3x^3+2x^2 ?
The derivative of x^4-3x^3+2x^2 is 4x^3-9x^2+4x
What is the first derivative of x^4-3x^3+2x^2 ?
The first derivative of x^4-3x^3+2x^2 is 4x^3-9x^2+4x