What is the solution for f^'(x)=12x^3-63x^2-72x+4 ?

The solution for f^'(x)=12x^3-63x^2-72x+4 is f(x)=3x^4-21x^3-36x^2+4x+c_{1}

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f^'(x)=12x^3-63x^2-72x+4

f^{^{'}} (x) = 12 x^{3} - 63 x^{2} - 72 x + 4

f (x) = 3 x^{4} - 21 x^{3} - 36 x^{2} + 4 x + c_{1}

Solution steps

f^{'} (x) = 12 x^{3} - 63 x^{2} - 72 x + 4

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 12 x^{3} - 63 x^{2} - 72 x + 4 d x

\int 12 x^{3} - 63 x^{2} - 72 x + 4 d x = 3 x^{4} - 21 x^{3} - 36 x^{2} + 4 x + c_{1}

f (x) = 3 x^{4} - 21 x^{3} - 36 x^{2} + 4 x + c_{1}

What is the solution for f^'(x)=12x^3-63x^2-72x+4 ?
The solution for f^'(x)=12x^3-63x^2-72x+4 is f(x)=3x^4-21x^3-36x^2+4x+c_{1}