What is the integral of x^2e^{4x^3} ?

The integral of x^2e^{4x^3} is 1/12 e^{4x^3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of x^2e^{4x^3}

\int x^{2} e^{4 x^{3}} d x

\frac{1}{12} e^{4 x^{3}} + C

Solution steps

\int x^{2} e^{4 x^{3}} d x

Apply u-substitution

= \int \frac{e ^{u}}{12} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{12} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{12} e^{u}

Substitute back

u = 4 x^{3}

= \frac{1}{12} e^{4 x^{3}}

Add a constant to the solution

= \frac{1}{12} e^{4 x^{3}} + C

What is the integral of x^2e^{4x^3} ?
The integral of x^2e^{4x^3} is 1/12 e^{4x^3}+C