What is the integral of 5/(\sqrt[4]{x^2)} ?

The integral of 5/(\sqrt[4]{x^2)} is 10sqrt(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 5/(\sqrt[4]{x^2)}

10 x + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 5 \cdot \int \frac{1}{x} d x

Apply the Power Rule

= 5 \cdot 2 x^{\frac{1}{2}}

Simplify

5 \cdot 2 x^{\frac{1}{2}} : 10 x

= 10 x

Add a constant to the solution

= 10 x + C

What is the integral of 5/(\sqrt[4]{x^2)} ?
The integral of 5/(\sqrt[4]{x^2)} is 10sqrt(x)+C