What is the integral from 0 to pi of x^2cos(nx) ?

The integral from 0 to pi of x^2cos(nx) is (2pi(-1)^n)/(n^2)

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integral from 0 to pi of x^2cos(nx)

\int_{0}^{π} x^{2} cos (n x) d x

\frac{2 π ( - 1 ) ^{n}}{n ^{2}}

Solution steps

\int_{0}^{π} x^{2} cos (n x) d x

Apply u-substitution

= \int_{0}^{nπ} \frac{u ^{2} cos ( u )}{n ^{3}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{n ^{3}} \cdot \int_{0}^{nπ} u^{2} cos (u) d u

Apply Integration By Parts

= \frac{1}{n ^{3}} [u^{2} sin (u) - \int 2 u sin (u) d u]_{0}^{nπ}

\int 2 u sin (u) d u = 2 (- u cos (u) + sin (u))

= \frac{1}{n ^{3}} [u^{2} sin (u) - 2 (- u cos (u) + sin (u))]_{0}^{nπ}

Compute the boundaries:

2 π (- 1)^{n} n

= \frac{1}{n ^{3}} \cdot 2 π (- 1)^{n} n

Simplify

= \frac{2 π ( - 1 ) ^{n}}{n ^{2}}

What is the integral from 0 to pi of x^2cos(nx) ?
The integral from 0 to pi of x^2cos(nx) is (2pi(-1)^n)/(n^2)