What is the solution for (dy)/(dx)=(2x+y+1)/(4x+2y-5) ?

The solution for (dy)/(dx)=(2x+y+1)/(4x+2y-5) is y=-2x+9/5-(7\W(-2/(7e^{(25x+c_{1))/7}}))/(10)

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(dy)/(dx)=(2x+y+1)/(4x+2y-5)

\frac{d y}{d x} = \frac{2 x + y + 1}{4 x + 2 y - 5}

y = - 2 x + \frac{9}{5} - \frac{7 W ( - \frac{2}{7 e ^{\frac{25 x + c _{1}}{7}}} )}{10}

Solution steps

\frac{d y}{d x} = \frac{2 x + y + 1}{4 x + 2 y - 5}

Solve using substitution:

y = - 2 x + \frac{9}{5} - \frac{7 W ( - \frac{2}{7 e ^{\frac{25 x + c _{1}}{7}}} )}{10}

y = - 2 x + \frac{9}{5} - \frac{7 W ( - \frac{2}{7 e ^{\frac{25 x + c _{1}}{7}}} )}{10}

What is the solution for (dy)/(dx)=(2x+y+1)/(4x+2y-5) ?
The solution for (dy)/(dx)=(2x+y+1)/(4x+2y-5) is y=-2x+9/5-(7\W(-2/(7e^{(25x+c_{1))/7}}))/(10)