derivative of (x+csc(x^3+3)^{-3})

Lösung

\frac{d}{d x} ((x + csc (x^{3} + 3))^{- 3})

- \frac{3 ( 1 - 3 x ^{2} cot ( x ^{3} + 3 ) csc ( x ^{3} + 3 ) )}{( x + csc ( x ^{3} + 3 ) ) ^{4}}

Schritte zur Lösung

\frac{d}{d x} ((x + csc (x^{3} + 3))^{- 3})

Wende die Kettenregel an:

- \frac{3}{( x + csc ( x ^{3} + 3 ) ) ^{4}} \frac{d}{d x} (x + csc (x^{3} + 3))

= - \frac{3}{( x + csc ( x ^{3} + 3 ) ) ^{4}} \frac{d}{d x} (x + csc (x^{3} + 3))

\frac{d}{d x} (x + csc (x^{3} + 3)) = 1 - cot (x^{3} + 3) csc (x^{3} + 3) \cdot 3 x^{2}

= - \frac{3}{( x + csc ( x ^{3} + 3 ) ) ^{4}} (1 - cot (x^{3} + 3) csc (x^{3} + 3) \cdot 3 x^{2})

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{3 ( 1 - 3 x ^{2} cot ( x ^{3} + 3 ) csc ( x ^{3} + 3 ) )}{( x + csc ( x ^{3} + 3 ) ) ^{4}}

d er i v a t i v e y = \frac{e ^{x}}{8 x ^{4}}

n \to \infty lim (\frac{n ^{2}}{2 n - 1} sin (\frac{1}{n}))

\frac{d}{d x} (ln (x^{2} + 5))

\int 4 e^{4 x} d x

\int \frac{x}{x ^{3} + x ^{2} + 4 x + 4} d x