What is the derivative of (3xy+7^2) ?

The derivative of (3xy+7^2) is 6(3xy+7)(x(dy)/(dx)+y)

What is the first derivative of (3xy+7^2) ?

The first derivative of (3xy+7^2) is 6(3xy+7)(x(dy)/(dx)+y)

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\frac{d}{d x} ((3 x y + 7)^{2})

6 (3 x y + 7) (x \frac{d y}{d x} + y)

Solution steps

\frac{d}{d x} ((3 x y + 7)^{2})

Apply the chain rule:

2 (3 x y + 7) \frac{d}{d x} (3 x y + 7)

= 2 (3 x y + 7) \frac{d}{d x} (3 x y + 7)

\frac{d}{d x} (3 x y + 7) = 3 (x \frac{d y}{d x} + y)

= 2 (3 x y + 7) \cdot 3 (x \frac{d y}{d x} + y)

Simplify

= 6 (3 x y + 7) (x \frac{d y}{d x} + y)

What is the derivative of (3xy+7^2) ?
The derivative of (3xy+7^2) is 6(3xy+7)(x(dy)/(dx)+y)
What is the first derivative of (3xy+7^2) ?
The first derivative of (3xy+7^2) is 6(3xy+7)(x(dy)/(dx)+y)