What is the tangent of f(x)=sqrt(2x+77),\at x=2 ?

The tangent of f(x)=sqrt(2x+77),\at x=2 is y= 1/9 x+79/9

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tangent of f(x)=sqrt(2x+77),\at x=2

tangent of

f (x) = 2 x + 77, at x = 2

y = \frac{1}{9} x + \frac{79}{9}

Solution steps

Find the tangent point:

(2, 9)

Find the slope of

f (x) = 2 x + 77 : \frac{df ( x )}{d x} = \frac{1}{2 x + 77}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{9}

Find the line with slope m=

\frac{1}{9}

and passing through

(2, 9) : y = \frac{1}{9} x + \frac{79}{9}

y = \frac{1}{9} x + \frac{79}{9}

What is the tangent of f(x)=sqrt(2x+77),\at x=2 ?
The tangent of f(x)=sqrt(2x+77),\at x=2 is y= 1/9 x+79/9