What is the integral of 20xe^{-5x} ?

The integral of 20xe^{-5x} is -4e^{-5x}x-4/5 e^{-5x}+C

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integral of 20xe^{-5x}

\int 20 x e^{- 5 x} d x

- 4 e^{- 5 x} x - \frac{4}{5} e^{- 5 x} + C

Solution steps

\int 20 x e^{- 5 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \int x e^{- 5 x} d x

Apply u-substitution

= 20 \cdot \int \frac{e ^{u} u}{25} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \frac{1}{25} \cdot \int e^{u} u d u

Apply Integration By Parts

= 20 \cdot \frac{1}{25} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= 20 \cdot \frac{1}{25} (e^{u} u - e^{u})

Substitute back

u = - 5 x

= 20 \cdot \frac{1}{25} (e^{- 5 x} (- 5 x) - e^{- 5 x})

Simplify

20 \cdot \frac{1}{25} (e^{- 5 x} (- 5 x) - e^{- 5 x}) : - 4 e^{- 5 x} x - \frac{4}{5} e^{- 5 x}

= - 4 e^{- 5 x} x - \frac{4}{5} e^{- 5 x}

Add a constant to the solution

= - 4 e^{- 5 x} x - \frac{4}{5} e^{- 5 x} + C

What is the integral of 20xe^{-5x} ?
The integral of 20xe^{-5x} is -4e^{-5x}x-4/5 e^{-5x}+C