What is the tangent of f(x)=2x^3+4x^2-5x-3,\at x=-1 ?

The tangent of f(x)=2x^3+4x^2-5x-3,\at x=-1 is y=-7x-3

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tangent of f(x)=2x^3+4x^2-5x-3,\at x=-1

tangent of

f (x) = 2 x^{3} + 4 x^{2} - 5 x - 3, at x = - 1

y = - 7 x - 3

Solution steps

Find the tangent point:

(- 1, 4)

Find the slope of

f (x) = 2 x^{3} + 4 x^{2} - 5 x - 3 : \frac{df ( x )}{d x} = 6 x^{2} + 8 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 7

Find the line with slope m=

- 7

and passing through

(- 1, 4) : y = - 7 x - 3

y = - 7 x - 3

What is the tangent of f(x)=2x^3+4x^2-5x-3,\at x=-1 ?
The tangent of f(x)=2x^3+4x^2-5x-3,\at x=-1 is y=-7x-3