What is the first d/(dt)(t^2-2t) ?

The first d/(dt)(t^2-2t) is 2t-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

d/(dt)(t^2-2t)

\frac{d}{d t} (t^{2} - 2 t)

2 t - 2

Solution steps

\frac{d}{d t} (t^{2} - 2 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) - \frac{d}{d t} (2 t)

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (2 t) = 2

= 2 t - 2