What is the (cos(pi/x))^' ?

The (cos(pi/x))^' is (pisin(pi/x))/(x^2)

What is the first (cos(pi/x))^' ?

The first (cos(pi/x))^' is (pisin(pi/x))/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(cos (\frac{π}{x}))^{^{'}}

\frac{π sin ( \frac{π}{x} )}{x ^{2}}

Solution steps

(cos (\frac{π}{x}))^{'}

Apply the chain rule:

- sin (\frac{π}{x}) (\frac{π}{x})^{'}

= - sin (\frac{π}{x}) (\frac{π}{x})^{'}

(\frac{π}{x})^{'} = - \frac{π}{x ^{2}}

= - sin (\frac{π}{x}) (- \frac{π}{x ^{2}})

Simplify

- sin (\frac{π}{x}) (- \frac{π}{x ^{2}}) : \frac{π sin ( \frac{π}{x} )}{x ^{2}}

= \frac{π sin ( \frac{π}{x} )}{x ^{2}}

What is the (cos(pi/x))^' ?
The (cos(pi/x))^' is (pisin(pi/x))/(x^2)
What is the first (cos(pi/x))^' ?
The first (cos(pi/x))^' is (pisin(pi/x))/(x^2)