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Popular Calculus >

integral of 1+sin(θ)

Solution

\int 1 + sin (θ) d θ

Solution

θ - cos (θ) + C

Solution steps

\int 1 + sin (θ) d θ

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d θ + \int sin (θ) d θ

\int 1 d θ = θ

\int sin (θ) d θ = - cos (θ)

= θ - cos (θ)

Add a constant to the solution

= θ - cos (θ) + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 1+sin(θ) ?
The integral of 1+sin(θ) is θ-cos(θ)+C