What is the derivative of 4-3x^2 ?

The derivative of 4-3x^2 is -6x

What is the first derivative of 4-3x^2 ?

The first derivative of 4-3x^2 is -6x

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\frac{d}{d x} (4 - 3 x^{2})

- 6 x

Solution steps

\frac{d}{d x} (4 - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (4) = 0

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 - 6 x

Simplify

= - 6 x