What is the tangent of x^2+y^2=169,(5,-12) ?

The tangent of x^2+y^2=169,(5,-12) is y= 5/12 x-169/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of x^2+y^2=169,(5,-12)

tangent of

x^{2} + y^{2} = 169, (5, - 12)

y = \frac{5}{12} x - \frac{169}{12}

Solution steps

Find the slope of

x^{2} + y^{2} = 169 : \frac{d y}{d x} = - \frac{x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{12}

Find the line with slope m=

\frac{5}{12}

and passing through

(5, - 12) : y = \frac{5}{12} x - \frac{169}{12}

y = \frac{5}{12} x - \frac{169}{12}

What is the tangent of x^2+y^2=169,(5,-12) ?
The tangent of x^2+y^2=169,(5,-12) is y= 5/12 x-169/12