What is the limit as x approaches 9 of (x^2-17x+72)/(x-9) ?

The limit as x approaches 9 of (x^2-17x+72)/(x-9) is 1

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limit as x approaches 9 of (x^2-17x+72)/(x-9)

x \to 9 lim (\frac{x ^{2} - 17 x + 72}{x - 9})

1

Solution steps

x \to 9 lim (\frac{x ^{2} - 17 x + 72}{x - 9})

Simplify

\frac{x ^{2} - 17 x + 72}{x - 9} : x - 8

= x \to 9 lim (x - 8)

Plug in the value

x = 9

= 9 - 8

Simplify

= 1

What is the limit as x approaches 9 of (x^2-17x+72)/(x-9) ?
The limit as x approaches 9 of (x^2-17x+72)/(x-9) is 1