What is the tangent of f(x)=37x-16x^2,\at x=1 ?

The tangent of f(x)=37x-16x^2,\at x=1 is y=5x+16

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tangent of f(x)=37x-16x^2,\at x=1

tangent of

f (x) = 37 x - 16 x^{2}, at x = 1

y = 5 x + 16

Solution steps

Find the tangent point:

(1, 21)

Find the slope of

f (x) = 37 x - 16 x^{2} : \frac{df ( x )}{d x} = 37 - 32 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(1, 21) : y = 5 x + 16

y = 5 x + 16

What is the tangent of f(x)=37x-16x^2,\at x=1 ?
The tangent of f(x)=37x-16x^2,\at x=1 is y=5x+16